y+1(y^4-y^3+y^2-y+1)=

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Solution for y+1(y^4-y^3+y^2-y+1)= equation: 


Simplifying
y + 1(y4 + -1y3 + y2 + -1y + 1) = 0

Reorder the terms:
y + 1(1 + -1y + y2 + -1y3 + y4) = 0
y + (1 * 1 + -1y * 1 + y2 * 1 + -1y3 * 1 + y4 * 1) = 0
y + (1 + -1y + 1y2 + -1y3 + 1y4) = 0

Reorder the terms:
1 + y + -1y + 1y2 + -1y3 + 1y4 = 0

Combine like terms: y + -1y = 0
1 + 0 + 1y2 + -1y3 + 1y4 = 0
1 + 1y2 + -1y3 + 1y4 = 0

Solving
1 + 1y2 + -1y3 + 1y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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